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Specification t Title sound image enlargement device (stereo system having 02 speaker system ?
. In the playback system, from the 2nd speaker system 5, strike the existing inter-peak transfer
characteristic at the listener's ear 1. It has a group of filters that gives a sense of broadening and
# the filter group has two interview components with the first property of the system function
being 1) z), and the system function 1) A front 1 'tangent component fill consisting of a total of 4
filters with 2 cross component filters having characteristics of 2 (c). And the output of the cross
component filter 2111. Have a 2 yarn new blender for mixing, left. The four right-handed source
signals, each with four offenses, and five individual lines also have the direct component filter
and the black. Parallel input to the low pass filter. The outputs of the direct component filters are
respectively. The mixture is input to the mixer on the same side and mixed. Component filter
from the opposite system in the The sound image can be spread further outward than the
position of the two speakers by mixing the output from the mixer and inputting the output from
the mixer to the left and right speakers respectively! It is the sound expansion to which it takes it.
Large equipment. (2) The mixer has means for changing the mixing ratio, said mixing. Stereo
playback device by changing the ratio ?. The expansion range of the sound image is variable
when played back with.
2, the scope of claims
DETAILED DESCRIPTION OF THE INVENTION The present invention relates to a sound image
enlargement device, in particular to a loudspeaker of two. In a stereo playback system where the
system spacing is narrow, the apparent two speakers are widely spaced. The invention relates to
five methods and circuits of a sound image enlarging apparatus for enhancing a stereo effect.
Conventional stereo radio force section F tape record. -The gap between the left and right
speakers is narrow, such as Two speakers from the listener,-the opening angle seen from the
force. For a small stereo playback system, you usually receive 2 channel sources such as 1M
broadcast and tape with EndPage: 1. When I listened to it, I had the disadvantage that I could not
get enough stereo effects. The objects of the present invention are described above. It is an object
of the present invention to provide a stereo reproduction system in which sufficient stereo effect
can be obtained even when the distance between two speaker systems is narrow-5, without the
drawbacks of the prior art. For this purpose. In order to achieve the present invention, the sound
* 2 speed. A sound image magnifier that can be localized to the outside of the force, giving the
equivalent effect of widening the gap between the two apparent sound forces! Configured by the
circuit. I also tried to get rich stereo feeling and realism. ????? When expanding the
position of sound image localization, the expansion range is variable. First, the principles
underlying the present invention will be described. 1 ░ Generally, the sense of direction of the
sound source, sense of distance 9 is -Stere. What prescribes a sense of o is from the sound source
of the listener. Space transmission characteristics 2 when sound waves reach both ears. It is the
difference in the characteristics of the left and right ears of it. ??? These physical Mfl, mainly
the direction of arrival of the sound source and 2.1 are determined. Now, consider a stereo
reproduction space as shown in FIG. First, two speakers Sb, Ex. Are respectively arranged at
11g12 shown by solid lines. Further, the distance d between the two speakers Sr, 55n is, for
example, d, 3 o ?, and this two. And the middle point 16 of the straight line connecting the
speakers SL and Sx, and the perpendicular bisector 1! With respect to the straight line. ! Located
on -14. Distance with the listener 15 ???????????? It is considered that the sound
field of the reproduction space is symmetrical with respect to the vertical bisection IP 13-14. As
shown in FIG. 1, the space transfer characteristics at the tympanic membrane case on the same
side and the opposite side of the listener from the speaker are As (tm) and Ac, respectively. 0)
However, ? is only an angular frequency of 0. And in this case, the distance between the two
speakers SL and SR.
There is a 50cIIL and a narrow fc) between As (Q) and Acfn). One big difference is not seen, that
is, right and left. Because there is not enough difference in the information heard in the ear. Clear
stereo effect can not be obtained. Next is the first. Let us consider the case where the 22
loudspeakers SL and Ex are arranged at positions fl 17118 shown by broken lines in the figure.
In this case, the distance d between the two speakers Sp and Sx is, for example, d and 1 m. The
middle point of the straight line connecting the listener 15 and the two speakers SL and SR. The
distance to 16 is the same as in the previous case (17. 'The same side of the listener from the
speaker in this case'. And let the space transfer characteristics at the other drum @ 1 be Bp ((b),
Bc) respectively. In this case, the difference between the characteristics of the two speaker
speakers SL and SR 9 and the difference between the characteristics of Br) and Br (a>) clearly
appears particularly in the high frequency range. Nostalgia, the stereo effect is improved.
Therefore, as shown in solid lines in FIG. 1 ', the speakers SL and SRf are arranged at a position
11.12, respectively, and viewed using electricity [gT path]. It is to make stereo impression added
to localize the Suvy 77 Sy SR at the position of 17.18 respectively. It is the present invention that
was considered, but about this below. I will explain in detail. In Figure 1, the output of the
speaker, SL, SR is included. ???????????? On the eardrum of the listener when the
speakers, SL, SR are in the position of 11.12 respectively. When the sound pressure response at
19.110 is PL and PR, respectively, the equation of ? holds. PIJAlAcXL () = () () ..........
(SPRAcAzXRsAc where (A s ░) = () # between 12 speakers "Acy'h gap is Space transfer matrix in
the case of 5acIIL. Next, output XL and XR from the 17.18 position respectively. Assuming that
sound pressure on the tympanic membrane of the listener when emitted is PL 'and PR',
respectively, the following equation is similarly established.
Roadside B ,? In B, (B) = () U between two speakers. There is a space transfer ma) IJ Fux when
BcIh gap is 1m. One set (2) r / 'X can be transformed as follows. PL'lfh EcAtAc-IAsAtXL () = (X)
(PYBeE, AcAsAcA) (XR) "" ..... =-(S) The last two of the right side of the above equation are the
right side of the equation (1) Same as
Later, it is the part that is given by the actual space transfer characteristics EndPage: 2.
Therefore, in order to interpret the sound emitted from the places 111 and 12 to the position
17.18 apparently, it is sufficient to provide (B) CA "by an electric circuit. Note that (Atj) -1 is a
part that cancels the existing space transfer characteristic, and (B) is a part that widens the
distance between the two speakers 5 of L and L. Thus, the matrix to be given by the electrical
circuit. Will be like a long time. Therefore, the electric circuit of the sound image enlarging device
is D, v, l) c. A matrix with an equalizer with frequency characteristics that It will be good if it
consists of circuits 0 like this. A block diagram of the electrical circuit is shown in FIG. 12 Figure.
21.22 is the left channel and right respectively. +1 ?, Equalizer for realization li: Qe, 25.26 each
1) Equalizer for realizing 1) s?! , 29, 210 JfX respectively for the left channel and the right
channel / channel output terminal 0 or less, an embodiment of the sound image enlargement
apparatus according to the present invention using the drawings. : To clarify. Existing space
transfer characteristics. It cancels and adds the function to enlarge the sound image anew. The
elements 1) s, l) c of the space transfer matrix with the side. According to the fixed results, they
all have a peak near 2 UkHz, are flat at 1 kHz or less, and exhibit relatively gentle cutoff
characteristics at 52 "kHz or more. ?????????????????? Height and cut-off
sharpness are different. Thus, to demonstrate lh and l) C, use, for example, an active filter. These
three characteristics are, for example, #i 2.5 as indicated by the broken lines in FIG. Second-order
low-pass filter, with peak at kllz. First-order low-pass through with a cutoff frequency of 7 to
akHz. Combine the two filters with the filter. ???? The fourth vIi is a diagram showing a basic
21 for realizing Dz, l) c and a circuit, and a portion surrounded by a broken line is a second-order
?low-pass filter having a resonant frequency at 2 and 5 kHz by the operational amplifier 42 , A
part surrounded by a dotted line. The 1st-order low band where the minute has a cutoff
frequency at BkHz. It is a pass filter. In FIG. 4, OBEA 3 amp 41 and resistance Ra2. ??????
??????? And the operational amplifier 43 and the resistor "Ra4. ???? Ra6 forms a
mixer and is secondary.
And the outputs from the first-order low pass filter. It is determined by the ratio of the resistance
ratio of l ? resistance Ras to the resistance R46, and this is the mixing ratio when this addition is
performed. The characteristics of Dz (c) and I) c "(b) can be given by appropriately setting the
ratio of. Fig. 5 shows the realization of l) z and Dcf as described above. An example of the sound
three-image enlargement circuit configured by the next equalizers EQs and EQc to be performed
is shown. FIG. As you wonder, the left and right channel input terminals. The signal from 51.52 is
l),? To imitate) directly. Component filter 53.56 and cross to simulate 77 ropes. Through the
component filter 54.5F), 2 in the mixers 1518 and 519! . Sent. Further, interlocked variable
resistors 511 and 512 are used. By changing the level of the OX component. The degree of
sound image enlargement can be changed. ?????? R15 ?#? is a resistor for setting the
level of the direct component. The 0 mixers F118 and 519 have respective resistors 259 and
Fi15 and an operational amplifier 57.58, and resistors R10 and 514 for setting the gain of the iI
operational amplifier, respectively. The output from the left and right channels, the port taken
out from the output terminal Fi 16 517. By connecting these output terminals to the terminal of
Zbeeka, the reproduction * field where the sound image is enlarged to the listener at the zero
position of the foot. It can be removed. As explained above, according to the present invention,
the step. Simple frequency response in the Leo reproduction system. Since this filter circuit can
have an effective sound image magnification of 3% by 7t, this device! ????????????
????????????? Stereo playback equipment with a narrow gap between right and
left speakers. For many users by incorporating it into the New functions not implemented in the
conventional method EndPage: 3 can be easily provided.
4. Brief description of the drawings Fig. 1 shows the arrangement of speakers and the
relationship between listeners and liF. Explanatory drawing which shows the concept of an
engagement and space transfer characteristic. Fig. 2 is a block diagram showing the space
transfer Madric 5F circuit for sound expansion, and Fig. 5 is the soundness expansion time. A
method of dividing the characteristics when realizing the path will be described. AFIlj is each
block of the sound image enlargement circuit. FIG. 5 is a circuit diagram showing a basic circuit
of the lock, and FIG. 5 is a circuit diagram showing an example of the sound image enlargement
circuit 9 in an embodiment of the present invention. The sign of the theory - - 15 to Akira ........ - ...
the listener, 21.22 .............. input terminal, 25.24,25. 26 иииииииииииииии Equalizer. 29.210 ............. of force
terminal, 341.42.45 ... song ..... songs op-amp. 51.52 и и и и и и и и и и и и и и и Input terminal. 3, 5, 6
иииииииииииииииииии 4 i contact 7 min. 54.55 .............. A cross component filter. ??????? ...... ! i14 иии и и
и и и и bent pile. st6. st7 и и и и и и и и и и и и и и и и Constant power terminal ?? = 71, t Figure I! Call
dispute 2 figure $ 38 ? 4 EndPage: ?
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